How to Calculate Steel Quantity in
a Column (BBS Guide)
Calculating the quantity of steel in a column (Bar Bending Schedule -
BBS) is essential for civil engineering projects. This guide simplifies the
process using a practical example.
Example Scenario
- Column Specs: Height = 3 m,
Cross-section = 500 x 400 mm
- Vertical Bars: 6 nos.,
Diameter = 16 mm
- Stirrups: Diameter = 8
mm, Spacing = 150 mm and 200 mm at L/3 respectively
- Clear Cover: 40 mm (large
columns)
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Step-by-Step Calculation
Step 1: Longitudinal Bars Calculation
- Formula: Length of 1
Rod = Height (H) + Development Length (Ld)
- H = 3000 mm
- Ld = 50d (d =
diameter of bar)
- Length of 1 Rod:
- = 3000 +
50(16)
- = 3000 + 800
- = 3800 mm or
3.8 m
- Total Length:
- 6 bars x 3.8 m
= 22.8 m of 16 mm bar
Step 2: Cutting Length of Rectangular
Stirrups
Dimensions After Clear Cover
Side |
Original (mm) |
Clear Cover (mm) |
Adjusted (mm) |
A |
500 |
2 x 40 |
420 |
B |
400 |
2 x 40 |
320 |
Number of Stirrups
- Zones: L/3 = 3000/3
= 1000 mm
- Top Zone: 1000 / 150 =
7 nos
- Bottom Zone: 1000 / 150 =
7 nos
- Mid Zone: 1000 / 200 =
5 nos
- Total Stirrups: 7 + 5 + 7 + 1
= 20 nos
Cutting Length of One Stirrup
- Formula: Cutting
Length = 2(a + b) + 2(9d) – 3(2d) – 2(3d)
- a = 420 mm, b
= 320 mm, d = 8 mm
- Calculation:
- = 2(500 + 400)
+ 2(9x8) – 3(2x8) – 2(3x8)
- = 1800 + 144 –
48 – 48
- = 1848 mm or
1.84 m
- Total Length: 20 x 1.84 =
36.8 m of 8 mm bar
Final Steel Quantity
Component |
Quantity |
Diameter |
Longitudinal Bars |
22.8 m |
16 mm |
Rectangular
Stirrups |
36.8 m |
8 mm |
Note: For steel weight, use formula D²/162 for 1 m. Learn more .
Dive Deeper
Want detailed formulas and tips? Check out the for more on BBS and steelquantity estimation in civil engineering.
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