SEMI‐ROUND STAIR‐CASE CALCULATION | QUANTITY SURVEY | VOLUME OF CONCRETE & AREA OF SHUTTERING
For a given drawing of a Semi‐round Stair‐case find
1. Volume of Concrete
2. Area of Shuttering
Height
of riser = 0.15m
Tread
= 0.10m
Radius
of waist Slab = 3.50m
Height
of Ceiling = Height of Riser x No. of Riser
= 0.15 x 24
= 3.60m
Waist
Slab thickness = 0.15m
Width
of Waist Slab = 1.30m
no.
of Step = 24
(A) Solution for staircase:
To find out Semi‐Circle
Length the formula = 2 x π x r x 0.50 Therefore,
Radius of waist slab 'r'= 3.50m
= 2 x π x 3.5 x 0.50
=
10.99m (linear length)
Inclined length = √(10.992
+ 3.602)
C =
11.56m
1. Waist Slab:
(a)
Volume of Concrete for waist slab = Area x thickness
= L x B x D
= 11.56 x 1.30 x 0.15
=
2.254 m3
(b)
Shuttering Area for waist slab = L x D x 2 + B x D + L x
B
= 11.56 x 0.15 x 2 + 1.30 x 0.15 + 11.56 x 1.30
=
18.691 m2
2. Steps:
Length of step = 1.30m
Width of tread = 0.30m on one side and 0.40m on other
side Average width of riser = (0.30 + 0.40)/2
B = 0.35m
Height of Riser = 0.15m
(a)
Volume of Concrete for Step = Area x length of step x no. of steps
= 1/2 x b x h x L x no. of steps
= 0.50 x 0.35 x 0.15 x 1.3 x 24
=
0.819 m3
(b)
Shuttering area for Step = (1/2 x B x H x 2 + L x D) x no.s
= (0.50 x 0.35 x 0.15 x 2 + 1.30 x 0.15) x 24
=
5.94 m2
3. Hand‐Rail :
Therefore,
L = 11.56m
B = 0.10m D = 0.80m
no.s = 2
(a)
Volume of Concrete for Hand‐Rail = area x depth x no. of
Hand rails
= L x B x D x no.s
= 11.56 x 0.10 x x 0.80 x 2
=
1.849 m3
(b)
Shuttering area for Hand‐Rail = (L+B) x 2 x D x no.s
= (11.56 + 0.10) x 2 x 0.80 x 2
=
37.312 m2
(i)
Total Concrete for stair case = 2.254 + 0.819 + 1.849
=
4.922 m3
(ii)
Total Shuttering area for stair‐case = 18.691 + 5.94 + 37.312
=
61.943 m2
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